If a motor running at a rate of 1200 revolutions per minute can supply torque of 80 Nm, then the power required will be

Question

If a motor running at a rate of 1200 revolutions per minute can supply torque of 80 Nm, then the power required will be

If a motor running at a rate of 1200 revolutions per minute can supply torque of 80 Nm, then the power required will be
A. `10 pi` kwatt
B. `192 pi` kwatt
C. `3.2 pi` kwatt
D. `40 pi ` kwatt

Monjur Alahi

8 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`P = tau omega = 80xx 2pi xx n`
`= (80xx pi xx 1200)/(60)=3.2 pi K w`

8 views Answered 2023-02-05 15:29