The radius of gyration of flywheel is `(3//pi)m` and its mass is 1 kg. If the speed of the flywheel is changed from 20 rpm to 60 rmp, then the work do
The radius of gyration of flywheel is `(3//pi)m` and its mass is 1 kg. If the speed of the flywheel is changed from 20 rpm to 60 rmp, then the work done would be
A. 16 J
B. 12 J
C. 24 J
D. 32 J
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Correct Answer - A
Work done = Change in K.E.
`K.E. = (1)/(2)I (omega_(2)^(2)-omega_(1)^(2))`
`=(1)/(2)m k^(2)4 pi^(2)(n_(2)^(2)-n_(1)^(2))`
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