A satellite of mass m is orbiting the earth at a height h from its surface. If M is the mass of the earth and R its radius, the kinetic energy of the
A satellite of mass m is orbiting the earth at a height h from its surface. If M is the mass of the earth and R its radius, the kinetic energy of the stellite will be
A. `-(GmM)/((R+h)^(2))`
B. `(GmM)/(2(R+h)^(2))`
C. `(GmM)/((R+h))`
D. `(GmM)/(2(R+h))`
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Correct Answer - d
`K.E.=(1)/(2)mv_(c)^(2)`
`=(1)/(2)m(GM)/(r)=(1)/(2)(GMm)/((R+h))`
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