The pitentil energy of a satellite is given as `PE= lambda(KE)` where PE = potential energy of the satellite KE = kinetic energy of the satellite The

Question

The pitentil energy of a satellite is given as `PE= lambda(KE)` where PE = potential energy of the satellite KE = kinetic energy of the satellite The

The pitentil energy of a satellite is given as
`PE= lambda(KE)`
where PE = potential energy of the satellite
KE = kinetic energy of the satellite
The vlaue of constant `lambda` is
A. `-2`
B. 2
C. `-1//2`
D. `+1//2`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
PE of satellite `=(GmM_(E))/(R_(E)+h)`
`KE of satellite =1/2 (GmM_(E))/(R_(E)+h)`
KE of satellite `=1/2 (GmM_(E))/(R_(E)+h)`
`PE=-2 KE rarr lambda =-2`

4 views Answered 2023-02-05 15:29