A coin of 4 g mass is placed at a distance of 2 cm from the axis of rotation a disc,. If the frequancy of disc is 180 rpm, then the coefficient of fri

Question

A coin of 4 g mass is placed at a distance of 2 cm from the axis of rotation a disc,. If the frequancy of disc is 180 rpm, then the coefficient of fri

A coin of 4 g mass is placed at a distance of 2 cm from the axis of rotation a disc,. If the frequancy of disc is 180 rpm, then the coefficient of friction between the coin at rest and disc will be
A. `0.07249`
B. `7.249`
C. `72.49`
D. `0.7250`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`cf=mu mg therefore mu =(r omega ^(2))/(g)=0.7250`

5 views Answered 2023-02-05 15:29