In the `Cr^(+2), Mn^(+3), Fe^(+2)` and `CO^(+3)` ions, number of unpaired electrons and magnetic moment wiII be
In the `Cr^(+2), Mn^(+3), Fe^(+2)` and `CO^(+3)` ions, number of unpaired electrons and magnetic moment wiII be
A. 3, 3.87
B. 4, 4.90
C. 3, 2.83
D. 1, 1.73
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Correct Answer - B
`Cr^(2+) , Mn^(3+),Fe^(2+) , CO^(3+)` has same no. of unpaired `e^-` in 3d orbitals, viz., 4.
`therefore` Magnetic moment will be `sqrt(4(4+2))` =4.90 B.M.
Formula is `sqrt(n(n+2))` B.M. where n is no. of unpaired `e^-` in 3d orbitals
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