The magnetic moment of a transition metal ion is 3.87BM. The number of unpaired electrons present in it is
The magnetic moment of a transition metal ion is 3.87BM. The number of unpaired electrons present in it is
A. 2
B. 3
C. 4
D. 5
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Correct Answer - B
`3.87=sqrt(n(n+2))`, where, n is the number of unpaired electrons.
solving n, we get,
`(3.87)^(2)=n(n+2)implies15=n^(2)+2n`
`n^(2)+2n-15=0`
`n=3`
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