The rate of law for the reaction `xA+yB=mP+nQ` is Rate `k[A]^(c)[B]^(d)`. What is the total order of reaction ?

Question

The rate of law for the reaction `xA+yB=mP+nQ` is Rate `k[A]^(c)[B]^(d)`. What is the total order of reaction ?

The rate of law for the reaction `xA+yB=mP+nQ` is Rate `k[A]^(c)[B]^(d)`. What is the total order of reaction ?
A. (x+y)
B. (m+n)
C. (c+d)
D. `(x)/(y)`

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
Order is the sum of the powers to which the concentration terms are raised in the rate equation.
Hence, order is (c+d).

6 views Answered 2023-02-05 15:29