For a chemical reaction rate law is, rate `= k{A]^(2)[B]`. If [A] is doubled at constant [B], the rate of reaction
For a chemical reaction rate law is, rate `= k{A]^(2)[B]`. If [A] is doubled at constant [B], the rate of reaction
A. increases by a factor of 8
B. increases by a factor of 4
C. incr-eases by a factor of 3
D. increases by a factor of 2
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Correct Answer - B
Given,
Initial rate `= k [A]^(2) [B]`
if `[A]^(1) = 2 [A]`
Rate `k= [2A]^(2) [B] 4k [A]^(2) [B]`
Thus, if the concenration of A, [A] is doubled and that of [B] is constant, then initial rate increases by a factor of 4.
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