The normal activity of living carbon - containing matter is found to be about 15 decays per minute for every gram of carbon. This activity arises from
The normal activity of living carbon - containing matter is found to be about 15 decays per minute for every gram of carbon. This activity arises from the small proportion of radioactive `._(6)^(14)C` present with the stable carbon isotope `._(6)^(12)C`. When the organism is dead, its interaction with the atmosphere (which maintains the above equilibrium activity. ceases and its activity begins to drop. From the know half-life (5730 years.) of `._(6)^(14)C`, and the measured activity, the age of the specimen can be approximately estimated. This is the principle of `._(6)^(14)C` dating used in archaeology. Suppose a specimen from Mohenjodaro gives an activity of 9 decays per minute per gram of carbon. Estimate the approximate age of the Indus-Valley civilisation.
1 Answers
Here normal activity `R_(0)=15` decays/min
Present activity R = 9 decays/min,
T = 5730 yrs
Age t = ?
As activity is proportional to the number of radio active atoms, therefore
`(N)/(N_(0))=(R )/(R_(0))=(9)/(15)`
But `(N)/(N_(0))=e^(-lambda t)`
`e^(-lambda t)=(9)/(15)=(3)/(5)`
`e^(+lambda t)=(5)/(3)`
`lambda t log_(e )e = "log"_(e )(5)/(3)= 2.3026 log 1.6667`
`lambda t = 2.3026xx0.2218=0.5109`
`t = (0.5109)/(lambda)`
`lambda =(0.963)/(T)= (0.693)/(5730)y t^(-1)`
`therefore t = (0.5109)/(0.693//5730)=(0.5109xx5730)/(0.693)`
`t = 4224.3` years