If the work function for a certain metal is `3.2 xx 10^(-19)` joule and it is illuminated with light of frequency `8 xx 10^(14) Hz`. The maximum kinet
If the work function for a certain metal is `3.2 xx 10^(-19)` joule and it is illuminated with light of frequency `8 xx 10^(14) Hz`. The maximum kinetic energy of the photo-electrons would be
`(h = 6.63 xx 10^(-34) Js)`
A. `2.1xx10^(-19)J`
B. `3.2xx10^(-19)J`
C. `5.3xx10^(-19)J`
D. `8.5xx10^(-19)J`
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Correct Answer - A
Maximum `KE=-hv-phi_(0)`
`=6.63xx10^(-34)xx6xx10^(14)-3.2xx10^(-19)`
`=2.1xx10^(-19)J`
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