The work function of caesium metal is 2.14 eV . When light of frequency `6xx 10^(14)` Hz is incident on the metal surface , photomission of electrons

Question

The work function of caesium metal is 2.14 eV . When light of frequency `6xx 10^(14)` Hz is incident on the metal surface , photomission of electrons

The work function of caesium metal is 2.14 eV . When light of frequency `6xx 10^(14)` Hz is incident on the metal surface , photomission of electrons occurs . What is the
maximum kinetic energy of the emitted electrons

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Given, `phi_(0)=2.14 eV, v =6xx10^(14)Hz`
`KE_("max")=hv-phi_(0)=(6.63xx10^(-34)xx6xx10^(14))/(1.6xx10^(-19))-2.14 therefore KE_("max")=0.35 eV`

4 views Answered 2023-02-05 15:29