Tube A has both ends open while tube B has one end
closed. Otherwise they are identical. Their
fundamental frequencies are in the ratio
A. `4 : 1`
B. `2 : 1`
C. `1 : 4`
D. `1 : 2`

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1 Answers

Correct Answer - b
`therefore v/v_(o)=(v//2lambda)/(v//4lambda)= 2/1`

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