A uniform string of length `1.5` m has two successive harmonics of frequencies 70 Hz and 84 Hz. The speed of the wave in the string (in `ms^(-1)`) is

Question

A uniform string of length `1.5` m has two successive harmonics of frequencies 70 Hz and 84 Hz. The speed of the wave in the string (in `ms^(-1)`) is

A uniform string of length `1.5` m has two successive
harmonics of frequencies 70 Hz and 84 Hz. The
speed of the wave in the string (in `ms^(-1)`) is
A. 84
B. 42
C. 21
D. `10.5`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - b
`because v_(n)=n/(2l)"v"` ...(i)
and `v_(n+1)=(n+1)/(2l)"v"` ...(ii)
From Equ. (i) and (ii) we get
`v_(n+1)-v_(n)=v/(2l)`
`rArr 84-70=v/(2l`
`therefore v=2 xx1.5xx14=42 " ms"^(-1)`

5 views Answered 2023-02-05 15:29