The excess pressure inside a spherical drop of water is four times that of another drop. Then, their respective mass ratio is
The excess pressure inside a spherical drop of water is four times that of another drop. Then, their respective mass ratio is
A. `1:16`
B. `8:1`
C. `1:4`
D. `1:64`
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Correct Answer - D
Excess pressure inside a spherical drop of water,
`p = (2T)/(R)`
Given, `p_(1) = 4p_(2)`
`(2T)/(R_(1)) = 4 xx (2T)/(R_(2)) rArr R_(2) = 4R_(1)`
Now, `(m_(1))/(m_(2)) = (4pi R_(1)^(3)d_(1))/(4pi R_(2)^(3)d_(2)) = (R_(1)^(3))/(R_(2)^(3)) = (1)/(64)`
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