The exess pressure inside a drop of soap solution is Pd and that inside a soap bubble of same radius is` P_(d)` then
The exess pressure inside a drop of soap solution is Pd and that inside a soap bubble of same radius is` P_(d)` then
A. `P_(d)=P_(b)`
B. `P_(b)=2P_(d)`
C. `P_(d)=2P_(b)`
D. `P_(b)=4P_(d)`
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Correct Answer - B
` P_(d) = (2T)/r`
`P_(b) = (4T)/r `
` (P_(b))/(P_(d))= (4T)/r xx r/(2T) = 2 `
` P_(b)=2P_(d)`
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