In an astronomical telescope, the focal length of the objective lens is 100 cm and of eye-piece is 2 cm . The magnifying power of the telescope for the normal eye is
A. 50
B. 10
C. 100
D. `(1)/(50)`

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1 Answers

Correct Answer - A
Magnification of astronomical telescope for normal eye is,
`m=(f_(o))/(f_(e ))=-(100)/(2)=-50`

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