The following data were obtained during the first order thermal decomposition of `SO_(2)CI_(2)` at a constant volume. `SO_(2)CI_(2(g)) to SO_(2(g)) +
The following data were obtained during the first order thermal decomposition of `SO_(2)CI_(2)` at a constant volume.
`SO_(2)CI_(2(g)) to SO_(2(g)) + CI_(2(g))`
`{:("Experiment","Time"//s^(-1),"Total pressure"//"atm"),(1,0,0.5),(2,100,0.6):}`
What is the rate of reaction when total pressure is 0.65 atm?
A. `0.35 atm s^(-1)`
B. `2.235 xx 10^(-3) atm s^(-1)`
C. `7.8 xx 10^(-4) atm s^(-1)`
D. `1.55 xx 10^(-4) atm s^(-1)`
1 Answers
Correct Answer - C
`SO_(2) CI_(2) to SO_(2) + CI_(2)`
initial pressure `P_(0) 0 0`
Pressure at time t `P_(0) - p, p p`
Let initial pressure `P_(0) Prop R_(0)`
Pressure at time, t, `P_(t) = P_(0) - p + p + p = P_(0) + p`
pressure of reactants at time t,`P_(0) - p = 2P_(0) - p_(t) prop R`
`k = (2.303)/(t) "log" (p_(0))/(p_(0) - p_(t))`
`= (2.303)/(100) "log" (0.5)/(2 xx 0.5 - 0.6) = (2.303)/(100) 1.25`
`= 2.2318 xx 10^(-3) s^(-1)`
Pressure of `SO_(2)CI_(2)` at time `t (p_(SO_(2)CI_(2)))`
`= 2P_(0) - P_(t) = 2 xx 0.50 - 0.65 atm = 0.35 atm`
rate at that time `= k xx P_(SO_(2)CI_(2))`
`= (2.2318 xx 10^(-3)) xx (0.35) = 7.8 xx 10^(-4) atm s^(-1)`