By a change of current from 5 A to 10 A in 0.1 s, the self induced emf is 10 V. The change in the energy of the magnetic field of a coil will be

Question

By a change of current from 5 A to 10 A in 0.1 s, the self induced emf is 10 V. The change in the energy of the magnetic field of a coil will be

By a change of current from 5 A to 10 A in 0.1 s, the self induced emf is 10 V. The change in the energy of the magnetic field of a coil will be
A. 5J
B. 6J
C. `7.5J`
D. 9J

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - C
` |epsi|=L(DeltaI)/(Deltat)`
`L=(|epsi|)/(DeltaI)=(10xx0.1)/((10-5))=0.2H`
The magnetic field energies for currents `I_(1) and I_(2)` are `U_(1)=(1)/(2)LI_(1)^(2) and U_(2)=(1)/(2)LI_(2)^(2)`
Change I energy `= U_(2)-U_(1)`
`=(1)/(2)LI_(2)^(2)=-(1)/(2)LI_(2)^(2)=(L)/(2)(I_(2)^(2)-I_(1)^(2))`
`=(0.20)/(2)(10^(2)-5^(2))7.5J`