A galvanometer of resistance `70 Omega`, is converted to an ammeter by a shunt resistance `r_(3) = 0.03 Omega`. The value of its resistance will becom
A galvanometer of resistance `70 Omega`, is converted to an ammeter by a shunt resistance `r_(3) = 0.03 Omega`. The value of its resistance will become
A. `0.025 Omega`
B. `0.022Omega`
C. `0.035Omega`
D. `0.030Omega`
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Correct Answer - D
`R=(R_(G)r_(s))/(R_(G) + r_(s))`
Here, `R_(G) = 70 Omega, r_(s) = 0.03 Omega`
`therefore R=(70 xx 0.03)/(70 +0.03) = 0.02998 = 0.03 Omega`
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