The number of electrons that must be removed from an electrically neutral silver dollar to give it a charge of +2.4C is
A. `2.5xx10^(19)`
B. `1.5xx10^(19)`
C. `1.5xx10^(-19)`
D. `2.5xx10^(-19)`

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Correct Answer - B
Total charge, q = + 2.4 C
Then by quantization of charge, q = ne
`therefore" "` number of electrons, `n=q/e=(2.4C)/(1.6xx10^(-19)C)=1.5xx10^(19)`

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