How many moles of sucrose should be dissolved in 500 g of water so as to get a solution which has a difference of `103.57^(@)C` between boiling point

Question

How many moles of sucrose should be dissolved in 500 g of water so as to get a solution which has a difference of `103.57^(@)C` between boiling point

How many moles of sucrose should be dissolved in 500 g of water so as to get a solution which has a difference of `103.57^(@)C` between boiling point and freezing point :-
`(K_(f)=1.86" K kg mol"^(-1), K_(b)="0.52 K kg mol"^(-1))`
A. `0.5` moles
B. `0.9` moles
C. `0.75` moles
D. `0.65` moles

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`because" "T_(b)=T_(b)^(@)=K_(b)xxm" …(i)"`
`" "T_(f)^(@)-T_(f)=K_(f)xxm" …(ii)"`
`"(i) equation "+" (ii) equation"`
`(T_(b)-T_(f))+(T_(f)^(@)-T_(b)^(@))=m(K_(b)-K_(f))`
`103.57-100=m(1.86+0.52)`
`(3.57)/(2.38)=(n)/(500)xx1000`
`0.75" moles"`

4 views Answered 2023-02-05 15:29