If `vecA=2hati+hatj-hatk. vecB=hati+2hatj+3hatk and vecC=6hati-2hatj-6hatk` then the angle between `(vecA+vecB) and vecC` will be :-
If `vecA=2hati+hatj-hatk. vecB=hati+2hatj+3hatk and vecC=6hati-2hatj-6hatk` then the angle between `(vecA+vecB) and vecC` will be :-
A. `30^(@)`
B. `45^(@)`
C. `60^(@)`
D. `90^(@)`
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Correct Answer - D
`vecA+vecB=vecD`
`vecD=3hati+3hatj+2hatk" , "vecC=6hati-2hatj-6hatk`
`vecDvecC=18-6-12=0`
`theta=90^(@)`
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