For a reaction rate `=K(A)^(1//2)(B)^(2)`. If concentration of A amd B are increased by factor of 4 and 2 respectively then rate is changed by the fraction :-
A. 4
B. 6
C. 8
D. None of these

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1 Answers

Correct Answer - C
`r=K(4)^(1//2)(2)^(2)`
`r=2xx2xx2rArr8 "times"`

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