A face centred cubic is made up of two types of atoms A and B in which A occupies the corner positions and B occupies the face centres. If atoms along
A face centred cubic is made up of two types of atoms A and B in which A occupies the corner positions and B occupies the face centres. If atoms along one of the body diagonal are removed, empirical formula of remainning solid will be
A. `AB_(2)`
B. `A_(3)B`
C. `A_(7)B_(3)`
D. `AB_(4)`
5 views
1 Answers
Correct Answer - D
A occupies corner `rArr8xx(1)/(8)`
B = occupies face centres `to6xx(1)/(2)=3` now, atoms along one body diagonal are removed `Ato6xx(1)/(8)=(3)/(4)`
Formula
`A_((3)/(4))B_(3)`
`rArrAB_(4)`
5 views
Answered