Silver crystallises in a face centred cubic unit cell. Each side of the unit cell has a length of 400 pm. Calculate radius of the silver atoms (Assume that the atoms just touch each other on the diagonal across the face of the unit cell i.e. each face atom is touching four atoms)

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Correct Answer - 141.4 pm
For a face centred (fcc) unit cell.
`r=(a)/(2sqrt2)or(("400pm"))/(2sqrt2)=((400xx10^(-10)))/(2sqrt2)`
`=((400xx10^(-10)cm))/(2xx1.414)=141.44xx10^(10)cm=141.4"pm"`

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