`A+BtoC+D`
`DeltaH=-10,000 J mol^(-1)`
`DeltaS-33.3 J mol^(-1)K^(-1)`
At what temperature the reaction will occur spontaneous from left to right ?
A. `=300.3K`
B. `gt300.3K`
C. `lt300.3K`
D. None of these

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1 Answers

Correct Answer - C
`DeltaG=0=0Delta-TDeltaS`
`T=(-10000)/(-3.3)=300.3K` Since `DeltaH&DeltaH` both are negative therefore reaction will be sportaneous at `Tlt300.3K`

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