Standard enthalpy of vapourisation `DeltaH^(@)` forwater is `40.66 KJ mol^(-1)`.The internal energy of vapourisation of water for its 2 mol will be :-

Question

Standard enthalpy of vapourisation `DeltaH^(@)` forwater is `40.66 KJ mol^(-1)`.The internal energy of vapourisation of water for its 2 mol will be :-

Standard enthalpy of vapourisation `DeltaH^(@)` forwater is `40.66 KJ mol^(-1)`.The internal energy of vapourisation of water for its 2 mol will be :-
A. `+43.76`
B. `+40.66`
C. `+37.56`
D. None of these

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`H_(2)O(l)toH_(2)O(g)`
`DeltaH^(@)=DeltaE^(@)+Deltan_(g)RT`
`40.66=66DeltaE^(@)+(1xx8.314xx373)/(1000)`
`DeltaE^(@)=+37.56KJ//mol`
for 2 mole `DeltaE^(@)=2xx37.26=75.12KJ`

4 views Answered 2023-02-05 15:29