The equilibrium constant for a reaction is 100 what will be the value of `DeltaG^(@)` ? `R=8.314JK^(-1)mol^(-1),T=300`K :-

Question

The equilibrium constant for a reaction is 100 what will be the value of `DeltaG^(@)` ? `R=8.314JK^(-1)mol^(-1),T=300`K :-

The equilibrium constant for a reaction is 100 what will be the value of `DeltaG^(@)` ? `R=8.314JK^(-1)mol^(-1),T=300`K :-
A. `-11488KJ`
B. `-11.488KJ`
C. `-12KJ`
D. `-12000KJ`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`DeltaG^(@)=-2.303RTlogK_(eq)`
`=-2.303xx8.314xx300log100J`
`DeltaG^(@)=-11.488KJ`

4 views Answered 2023-02-05 15:29