A certain weak acid has a disspciatoin constant `1.0xx10^(-4)`, the equilibrium constant for its reaction with strong base is :-
A. `1.0xx10^(-4)`,
B. `1.0xx10^(-10)`,
C. `1.0xx10^(10)`,
D. `1.0xx10^(14)`,

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Correct Answer - C
`K=(K_(a))/(K_(w))=10^(10)`

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