The wavelenth of a neutron with a translatory kinetic energy equal to KT at 300 K is :-
A. 178 pm
B. 200 pm
C. 17.8 pm
D. 20.0 pm

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1 Answers

Correct Answer - A
`lamda = (h)/(sqrt(2XK.Exm))`
`=(6.63xx10^(-34))/(sqrt(2xxKxxTxx1.67xx10^(-27)))`
`=(6.62xx10^(-34))/(sqrt(2xx(R)/N_(A)xx300xx1.67xx10(-27))`
= 178 pm

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