A capacitor of `2 muF` is charged to a potential of 4V using a battery, and then the battery is disconnected and the changed capacior is connected to
A capacitor of `2 muF` is charged to a potential of 4V using a battery, and then the battery is disconnected and the changed capacior is connected to an uncjharged caspacitor of `4 muF` capacitance. When the equilibrium is established the total energy stored in the capacitors is
A. `16 muJ`
B. `(16)/(3)muJ`
C. `(32)/(3)muJ`
D. `(32)/(9)muJ`
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Correct Answer - B
`V=(C_(1)V_(1)+C_(2)V_(2))/(C_(1)+C_(2))`
`U_(F)=1/2(C_(1)+C_(2))V^(2)`
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