In a potentiometer arrangement, a cell of emf 1.25 V gives a balance point at 35.0 cm length of the wire. If the cell is replaced by another cell and

Question

In a potentiometer arrangement, a cell of emf 1.25 V gives a balance point at 35.0 cm length of the wire. If the cell is replaced by another cell and

In a potentiometer arrangement, a cell of emf 1.25 V gives a balance point at 35.0 cm length of the wire. If the cell is replaced by another cell and the balance point shifts to 63.0 cm, what is the emf of the second cell ?

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Emf of the cell, `E_(1)=1.25 V`
Balance point of the potentiometer, `l_(1)=35` cm
The cell is replaced by another cell of emf `E_(2)`
New balance point of the potentiometer, `I_(2)=63` cm
The balance condition is given by the relation,
`(E_(1))/(E_(2))=(I_(1))/(I_(2))`
`E_(2)=E_(1)xx(l_(2))/(l_(1))`
`= 1.25 xx (63)/(35) = 2.25 V`
Therefore, emf of the second cell is 2.25 V.