For the reaction : `H_(2)+I_(2)to 2HI,` the differential rate law is

Question

For the reaction : `H_(2)+I_(2)to 2HI,` the differential rate law is

For the reaction : `H_(2)+I_(2)to 2HI,` the differential rate law is
A. `-(d[H_(2)])/(dt)=-(d[I_(2)])/(dt)=2(d[HI])/(dt)`
B. `-(d[H_(2)])/(dt)=-2(d[I_(2)])/(dt)=(d[HI])/(dt)`
C. `-(d[H_(2)])/(dt)=-(d[I_(2)])/(dt)=(d[HI])/(dt)`
D. `-(d[H_(2)])/(dt)=-(d[I_(2)])/(dt)=(d[HI])/(dt)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`H_(2)+I_(2) to 2HI`
Rate of reaction `=-(d[H_(2)])/(dt)=(-d[I_(2)])/(dt)=(1)/(2)(d[HI])/(dt)`
or `(-2d[H_(2)])/(dt)=(-2d[I_(2)])/(dt)=(d[HI])/(dt)`

4 views Answered 2023-02-05 15:29