Rate law for the reaction `A + 2B rarr C`, is found to be Rate = k [A] [B]. If the concentration of reactant B is doubled keeping the concentration of

Question

Rate law for the reaction `A + 2B rarr C`, is found to be Rate = k [A] [B]. If the concentration of reactant B is doubled keeping the concentration of

Rate law for the reaction `A + 2B rarr C`, is found to be Rate = k [A] [B]. If the concentration of reactant B is doubled keeping the concentration of A constant, the value of rate constant will be
A. the same
B. doubled
C. quadrupled
D. halved

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
Rate of reaction, `r_(1)=k[A][B]`
`r_(2)=k[A][2B]`
`r_(2)=2r_(1)`

4 views Answered 2023-02-05 15:29