Two moles of n ideal gas are allowed to expand from a volume of `10dm^(3)` to `m^(3)` at 300 K against a pressure of 101.325 kPa. Calculate the work d

Question

Two moles of n ideal gas are allowed to expand from a volume of `10dm^(3)` to `m^(3)` at 300 K against a pressure of 101.325 kPa. Calculate the work d

Two moles of n ideal gas are allowed to expand from a volume of `10dm^(3)` to `m^(3)` at 300 K against a pressure of 101.325 kPa. Calculate the work done
A. `-20.16kJ`
B. `13.22kJ`
C. `-810.6J`
D. `-18.96kJ`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - A
Given, Number of moles (n)=2
Intial volume `(V_(1))=10dm^(3)=0.01m^(3)`
`(because1dm^(3)=(1)/(1000)m^(3))`
Final volume `(V_(2))=2m^(3)`
`P_("ext")=101.325kPa`
Temperature (T) = 300k
`because` Work done due to charge in volume against a constant pressure is given by
`W=-P_("ext")(V_(2)-V_(1))`
`:." "w=-101.325kPaxx(2-0.0.1)m^(3)`
`=-201.636kPam^(3)or-201.6kJ`
`(because1kJ=akPam^(3))`