Interference fringes are produced on a screen by using two light sources of intensities / and 9/. The phase difference between the beams `pi/2` is at

Question

Interference fringes are produced on a screen by using two light sources of intensities / and 9/. The phase difference between the beams `pi/2` is at

Interference fringes are produced on a screen by using two light sources of intensities / and 9/. The phase difference between the beams `pi/2` is at point P and `pi`at point Q on the screen. The difference between the resultant intensities at point P and Q is
A. 2
B. 4
C. 6
D. 8

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - C
According to question, resultant intensity of interferring wave is given by
`l_P=l_2+2sqrt(l_1l_2cosphi)`
For `phi=pi/2,l_P=l+9l=10l`
Again at point Q, resultant intensity is given by
`l_Q=l_1+l_2+2sqrt(l_1l_2cosphi)`
`phi =pi,l_Q=l+9l+(-2sqrt(9(l)^2)`
`=10l-6l-4l`
Now, difference between the resultant intensity is given by `Deltal=l_P-l_Q=10l-4l=6l`