In a biprism experiment, light of wavelength 5200 Å is used to get an interference pattern on the screen. The fringe width changes by 1.3 mm when the

Question

In a biprism experiment, light of wavelength 5200 Å is used to get an interference pattern on the screen. The fringe width changes by 1.3 mm when the

In a biprism experiment, light of wavelength 5200 Å is used to get an interference pattern on the screen. The fringe width changes by 1.3 mm when the screen is moved towards biprism by 50 cm. Find the distance between two virtual image of the slit.

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Given, `lambda=5200"Å"=5.2 xx 10^(-7)m`
`X_(1)-X_(2)=1.3 mm =1.3 xx 10^(-3)m`
`D_(1)-D_(2)=50cm=0.5m`
We know that, `X_(1)-X_(2)=(lambda D_(1))/(d)-(lambda D_(2))/(d)`
`X_(1)-X_(2)=(lambda)/(d)(D_(1)-D_(2))`
`therefore d=(lambda(D_(1)-D_(2)))/(X_(1)-X_(2))`
`=(5.2xx10^(-7)xx0.5)/(1.3xx10^(-3))`
`=0.002 m`
`=0.2 mm`

4 views Answered 2023-02-05 15:29