`1/(sqrt(9)-sqrt(8))-1/(sqrt(8)-sqrt(7))+1/(sqrt(7)-sqrt(6))-1/(sqrt(6)-sqrt(5))+1/(sqrt(5)-sqrt(4))` के बराबर है।
`1/(sqrt(9)-sqrt(8))-1/(sqrt(8)-sqrt(7))+1/(sqrt(7)-sqrt(6))-1/(sqrt(6)-sqrt(5))+1/(sqrt(5)-sqrt(4))` के बराबर है।
A. 5
B. 1
C. 3
D. 0
4 views
1 Answers
Correct Answer - A
`1/(sqrt(9)-sqrt(8))xx(sqrt(9)+sqrt(8))/(sqrt(9)+sqrt(8))=(sqrt(9)+sqrt(8))/(9-8)`
`impliessqrt(9)+sqrt(8)`
Similarly `1/(sqrt(8)-sqrt(7))=sqrt(8)+sqrt(7)`
`1/(sqrt(7)-sqrt(6))=sqrt(7)+sqrt(6)`
`1/(sqrt(5)-sqrt(5))=sqrt(6)+sqrt(5)`
`=1/(sqrt(5)-sqrt(4))=sqrt(5)+sqrt(4)`
Now put in the question
`implies(sqrt(9)+sqrt(8))-(sqrt(8)+sqrt(7))+(sqrt(7)+sqrt(6))-`
`impliessqrt(9)+sqrt(8)-sqrt(8)-sqrt(7)+sqrt(7)+sqrt(6)-`
`sqrt(6)-sqrt(5)+sqrt(5)+sqrt(4)`
`impliessqrt(9)+sqrt(4)`
`implies3+2=5`
4 views
Answered