Hydrogen electrode is placed in the solution whose pH is 10. The potential of this electrode will be
Hydrogen electrode is placed in the solution whose pH is 10. The potential of this electrode will be
A. `+0. 591 V`
B. `- 0.591 V`
C. `0`
D. None of these
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Correct Answer - B
`E_(H^(+)//1/2H_(2))=E_(H^(+)//1/2H_(2))^(@)-0.0591/1"log "1/10^(-10)`
`=-0.0591xx10=-0.591 V`
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