The vapour pressure of a solution of a non-volatile electrolyte `B` in a solvent `A` is `95%` of the vapour pressure of the solvent at the same temper

Question

The vapour pressure of a solution of a non-volatile electrolyte `B` in a solvent `A` is `95%` of the vapour pressure of the solvent at the same temper

The vapour pressure of a solution of a non-volatile electrolyte `B` in a solvent `A` is `95%` of the vapour pressure of the solvent at the same temperature. If the molecular weight of the solvent is `0.3` times, the molecular weight of solute, the weight ratio of the solvent and solute are:
A. 0.15
B. 5.7
C. 0.2
D. 4

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

`2g` of a non-volatile hydrocarbon solute dissolved in `100g` of a hypothetical organic solvent (molar mass `=50`) was found to lower the vapour press

2 Answers 4 Views

Calculate the freezing point of a solution of a non-volatile solute in a unknown solvent of molar mass `30g//"mole"` having mole fraction of solvent e

2 Answers 4 Views

(a) `A` solution is prepared by dissolving `10g` of non-volatile solute in `180g` of `H_(2)O`. If the relative lowering of vapour pressure is `0.005`,

2 Answers 5 Views

Two beakers, one contaning `20ml` of a `0.05M` aqueous solution of a non volatile, non electrolyte and the other, the same volume of `0.03M` aqueous s

2 Answers 4 Views

How is relative lowering of vapour pressure defined for a solution consisting of volatile solvent and non-volatile solute ? How is this function relat

2 Answers 5 Views

When `36.0g` of a non -volatile, non-electrolyte solution an empirical formula `CH_(2)O` is dissolved inn`1.20Kg` of water. The solution freezes at `-

2 Answers 4 Views

Two solutions of non-volatile and non-electrolyte solute `A` and `B` are prepared separately. The molar mass ratio `(M_(A))/(M_(B))=1/3`. Both are pre

2 Answers 8 Views

The relative lowering of vapour pressure of an aqueous solution containing a non-volatile solute, is 0.0125. The molality of the solution is

2 Answers 4 Views

The vapour pressure of pure benzene is 640 mm of Hg. `2.175 xx 10^(-3)` kg of non-volatile solute is added to 39 gram of benzene, the vapour pressure

2 Answers 4 Views

Relative loweringof vapour pressure of a dilute solution is `0.2`. What is the mole fraction of non-volatile solute ?

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - B
`"P"_("solution")=0.95"P"_("solvent")^(0)`
` "m"_("solvent")=0.3" m"_("solute")`
`("P"_("solvent")^(0)-"P"_("solution"))/("P"_("solution"))=("W"_("solute")xx"m"_("solvent"))/("m"_("solute")xx"W"_("solvent"))`
`("P"^(0)-0.95"P"^(0))/(0.95"P"^(0))="W"_("solute")/"W"_("solvent")xx0.3`
`"W"_("solute")/"W"_("solvent")=0.3xx19=5.7`