For zero order reaction : `A+2Brarr"Product"` If initial concentration of A is 2a and rate law. `(-dB)/(dt)=K[A]^(o)[B]^(o)` then `t_(1//2)` of A will

Question

For zero order reaction : `A+2Brarr"Product"` If initial concentration of A is 2a and rate law. `(-dB)/(dt)=K[A]^(o)[B]^(o)` then `t_(1//2)` of A will

For zero order reaction :
`A+2Brarr"Product"`
If initial concentration of A is 2a and rate law.
`(-dB)/(dt)=K[A]^(o)[B]^(o)`
then `t_(1//2)` of A will be
A. `(a)/(2K)`
B. `(2a)/(K)`
C. `(a)/(K)`
D. `(a)/(3K)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - A
`E_("cell")=(2.303RT)/(F)xx log .[Ag^(+)]_("Cathode")/([Ag^(+)]_("anode"))`
`6xx10^(-2)=0.06 "log"(0.01)/([Ag^(+)]_("anode"))`
`[Ag^(+)]_("anode")=10^(-3)M`
`K_(sp)=|Ag^(+)|.^(2)|CrO_(4)^(-2)|=10^(-6)xx0.01=10^(-8)`
`10^(-8)=S^(2)xx 1 " "implies " "S=10^(-4)`
`10^(4) xx S = 10^(4) xx10^(-4) = 0 "or" 1`