A solution of substance containing `1.05` g per 100 mL was found to be isotonic with `3%` glucose solution . The molecular mass of the substance is :

Question

A solution of substance containing `1.05` g per 100 mL was found to be isotonic with `3%` glucose solution . The molecular mass of the substance is :

A solution of substance containing `1.05` g per 100 mL was found to be isotonic with `3%` glucose solution . The molecular mass of the substance is :
A. 31.54
B. 6.3 u
C. 630 u
D. 63 u

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`pi_(x)=pi_("glucose")`
`iC_(x)RT=iC_("glucose")RT`
`C_(x)=C_("glucose")`
`(1.05)/(MM)xx(1000)/(100)=(3g)/(180)xx(1000)/(100)`
`MM=63`

5 views Answered 2023-02-05 15:29