`1M` of glucose solution has a freezing point of `-1.86^(@)C` . If `10 ml` of `1M` glucose is mixed with `30 ml` of `3M` glucose then the resultant so

Question

`1M` of glucose solution has a freezing point of `-1.86^(@)C` . If `10 ml` of `1M` glucose is mixed with `30 ml` of `3M` glucose then the resultant so

`1M` of glucose solution has a freezing point of `-1.86^(@)C` . If `10 ml` of `1M` glucose is mixed with `30 ml` of `3M` glucose then the resultant solution will have a freezing point of
A. `-2.79^(@)C`
B. `-4.65^(@)C`
C. `-5.58^(@)C`
D. `-7.44^(@)C`

Monjur Alahi

7 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - 2
`DT_(f)=K_(f)xm`
`1.86=1.86xxmrArrm=1`
molality of `=(1xx1000)/((1000xxd-180))=1 rArr 1.18g//ml`
`M_(mix)=(10xx1+30xx3)/(40)=2.5M`
`DeltaT_(f)=-4.65^(@)C`
`T_(f)=-4.65^(@)C`

7 views Answered 2023-02-05 15:29