A certain solution of `1 m` benzoic acid in benzene has a freezing point of `3.1^(@)C` and a normal boiling point of `82.6 ^(@)C`. The freezing point

Question

A certain solution of `1 m` benzoic acid in benzene has a freezing point of `3.1^(@)C` and a normal boiling point of `82.6 ^(@)C`. The freezing point

A certain solution of `1 m` benzoic acid in benzene has a freezing point of `3.1^(@)C` and a normal boiling point of `82.6 ^(@)C`. The freezing point of benzene is `5.5^(@)C`. And its boiling point is `80.1^(@)C`. Analyze the state of the solute (benzoic acid ) at two temperature and comment .

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

`12.2gm` benzoic acid `(M =122)` in `100g H_(2)O` has elevation of boiling point of `0.27^(@)C, K_(b) = 0.54 K` kg/mole. If there is `100%` dimerizati

2 Answers 4 Views

The freezing point of `0.02 mol` fraction solution of acetic acid (A) in benzene (B) is `277.4K`. Acetic acid exists partly as a dimer `2A = A_(2)`. C

2 Answers 4 Views

when `1.80 g` of a nonvolatile solute is dissolved in `90 g` of benzene, the boiling point is raised to `354.11K`. If the boiling point of benzene is

2 Answers 4 Views

`1.22 g` of benzoic acid is dissolved in acetone and benzene separately. Boiling point of mixture with acetone increase by `0.17^(@)C` and boiling poi

2 Answers 10 Views

What is the percent by mass of iodine needed to reduce the freezing point of benzene to `3.5^(@)"C"`? The freezing point and cryoscopic constant of pu

2 Answers 4 Views

The freezing point of a solution containing 2.40 g of a compound in 60.0g of benzene is `0.10^(@)"C"` lower than that of pure benzene. What is the mol

2 Answers 5 Views

Phenol associates in benzene to a certain extent to form a dimer. A solution containing `20xx10^(-1)` kg phenol in 1 kg of benzene has its freezing pi

2 Answers 5 Views

`1.22 g` of benzoic acid is dissolved in (i) 100g acetone `(K_(b)` for acetone `=1.7)` and (ii) 100 g benzene `(K_(b)` for benzene `= 2.6)`. The eleva

2 Answers 4 Views

An aqueous glucose solution has boiling point of `374.19K`. Another aqueous glucose solution has a freezing point of `272.22K`. Find the molality rati

2 Answers 4 Views

The freezing point of 0.1 M solution of glucose is `-1.86^(@)C`. If an equal volume of 0.3 M glucose solution is added, the freezing point of the mixt

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - (a) benzoic acid may ionise
so that `i=(1+x)gt1`
`i=[1+((1)/(n)-1)xx]lt1`
(c) benzoic acid remains unchanged so that `i=1`
First we consider depression in freezing point of solution of molality `m`
`DeltaT_(f)=K_(f)mi`
`i=(DeltaT_(f))/(K_(f)m)=(5.5-3.1)/(5.12)=0.47`
We find `ilt1` (case b). Hence, there is association of benzoic acid in benzenen due to intermolecular `H-`bonding in freezing state.
For elevation in boiling point for the same solution of molality `m,DeltaT_(b)=K_(b)mi`
`i=(DeltaT_(b))/(K_(b)m)=(82.6-80.1)/(2.53)=0.99approx1.0`
we find `i=1` (case c). Hence, benzoic acid in benzene acid in benzenen in boiling state remains unchanged.