x gram of urea and y gram of glucose produce a freezing point depression of `0.186^(@)C` when both are dissolved in 100 ml water. If ration of `x:y=1:

Question

x gram of urea and y gram of glucose produce a freezing point depression of `0.186^(@)C` when both are dissolved in 100 ml water. If ration of `x:y=1:

x gram of urea and y gram of glucose produce a freezing point depression of `0.186^(@)C` when both are dissolved in 100 ml water. If ration of `x:y=1:2` then which is correct ? [ Molal freezing point depression constant for water `=1.86^(@)C//m &` density of water `=1` gram`//ml]`
A. `x=0.36` gram, `y=0.72` gram
B. `x=0.36` gram,`y=1.04` gram
C. `x=0.52` gram, `y=0.72`gram
D. `x=0.52` gram`,y=1.04`gram

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - 1
`DeltaT_(F)=k_(F)xxm`
`0.186=1.86[(x)/(60)+(y)/(180)]xx(1000)/(100)`
`(1)/(10)=(x)/(6)+(y)/(18)& (x)/(y)=(1)/(2)." On solving "x=0.36"gram "y=0.72"gram".`

5 views Answered 2023-02-05 15:29