The particle executing simple harmonic motion has a kinetic energy K0cos2ωt. The maximum values of the potential energy and the total energy are respectively

(a) K0/2 and K0

(b) Kand 2K0

(c) K0 and K0

(d) 0 and 2K0.

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1 Answers

Correct option  (c) K0 and K0

Explanation:

Kinetic energy+potential energy-total energy When kinetic energy is maximum, potential energy is zero and vice versa.

∴ Maximum potential energy = total energy.

0 + K= k0 (K.E. + P.E. = total energy).

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