A particle moves with simple harmonic motion in a straight line. In first t sec, after starting from rest,
A particle moves with simple harmonic motion in a straight line. In first t sec, after starting from rest, it travels a distance a and in next t sec, it travels 2a in same direction, then
(a) amplitude of motion is 3pi
(b) time period of oscillations is 5pi
(c) amplitude of motion is 4pi
(d) time period of oscillations is 6pi
2 Answers
In the first step it is given the displacement of the particle from the mean position, as a function of the time i.e
x=Acosωt
where, A is amplitude of motion of the particle and ω is its angular velocity.
So, at time t=0, the value of displacement x will be A (as cos0=1)
Hope you understand:)
I got it sir, but the thing is why you took a cosine fuction while there is sine? I mean is there any clue in the question that you should apply cosine to get the correct answer?
And the next is, (when t=t x=A-a) the doubt is at time t the body travelled distance 'a' but you took it as 'A-a' this step is soo confusing ?