One year ago, a man was 8 times as old as his son. Now his age is equal to the square of his son’s age. Find their present ages
One year ago, a man was 8 times as old as his son. Now his age is equal to the square of his son’s age. Find their present ages.
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Let the present age of the son be x years.
∴ Present age of man = x2 years
One year ago,
Son's age = (x − 1) years
Man's age = (x2 − 1) years
It is given that one year ago; a man was 8 times as old as his son.
∴ (x2 − 1) = 8(x − 1)
x2 − 8x − 1 + 8 = 0
x2 − 8x + 7 = 0
(x − 7) (x − 1) = 0
x = 7, 1
If x = 1, then x2 = 1, which is not possible as father's age cannot be equal to son's age.
Present age of son = x years = 7 years
Present age of man = x2 years = 49 years.
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