The present age of a man is 2 years more than five times the age of his son. Two years hence, the man’s age will be 8 years more than

Let the man’s present age be x years. 

Let his son’s present age be y years. 

According to the question, we have: 

Two years ago: 

Age of the man = Five times the age of the son 

⇒ (x – 2) = 5(y – 2) 

⇒ x – 2 = 5y – 10 

⇒ x – 5y = –8 …….(i) 

Two years later: 

Age of the man = Three times the age of the son + 8 

⇒ (x + 2) = 3(y + 2) + 8 

⇒ x + 2 = 3y + 6 + 8 

⇒ x – 3y = 12 …………(ii) 

Subtracting (i) from (ii), we get: 

2y = 20 

⇒ y = 10 

On substituting y = 10 in (i), we get: 

x – 5 × 10 = -8 

⇒ x – 50 = -8 

⇒ x = (-8 + 50) = 42 

Hence, the present age of the man is 42 years and the present age of the son is 10 years.